There were some pomegranates and pears in Box K and Box L. In Box K, the ratio of the pomegranates to the number of pears was 11 : 1. In Box L, the ratio of the number of pomegranates to the number of pears was 5 : 3. There were 3 times as many fruits in Box K as in Box L. After another 56 pears were put into Box L, the ratio of the number of pomegranates to the number of pears in Box L became 1 : 2. How many fruits were there in Box K?
Box K |
Box L |
3x8 = 24 u |
1x8 = 8 u |
Pomegranates |
Pears |
Pomegranates |
Pears |
11x2 |
1x2 |
5 |
3 |
22 u |
2 u |
5 u |
3 u |
The total number of fruits in Box K is repeated. Make the total number of fruits in Box K the same. LCM of 3 and 12 is 24.
The total number of fruits in Box L at first is repeated. Make the total number of fruits in Box L the same. LCM of 1 and 8 is 8.
|
Box K |
Box L |
|
Pomegranates |
Pears |
Pomegranates |
Pears |
Before |
22 u |
2 u |
5 u |
3 u |
Change |
|
|
|
+ 56 |
After
|
22 u
|
2 u
|
1x5 = 5 u |
2x5 = 10 u |
Number of pomegranates in Box L remains unchanged. Make the number of pomegranates in Box L the same. LCM of 5 and 1 is 5.
Number of pears put into Box L
= 10 u - 3 u
= 7 u
7 u = 56
1 u = 56 ÷ 7 = 8
Number of fruits in Box K
= 22 u + 2 u
= 24 u
= 24 x 8
= 192
Answer(s): 192