There were some pomegranates and lemons in Container H and Container J. In Container H, the ratio of the pomegranates to the number of lemons was 6 : 1. In Container J, the ratio of the number of pomegranates to the number of lemons was 4 : 3. There were 2 times as many fruits in Container H as in Container J. After another 20 lemons were put into Container J, the ratio of the number of pomegranates to the number of lemons in Container J became 1 : 2. How many fruits were there in Container H?

Container H		Container J
2x7 = 14 u		1x7 = 7 u
Pomegranates	Lemons	Pomegranates	Lemons
6x2	1x2	4	3
12 u	2 u	4 u	3 u

The total number of fruits in Container H is repeated.  Make the total number of fruits in Container H the same.  LCM of 2 and 7 is 14.

The total number of fruits in Container J at first is repeated.  Make the total number of fruits in Container J the same.  LCM of 1 and 7 is 7.

	Container H		Container J
	Pomegranates	Lemons	Pomegranates	Lemons
Before	12 u	2 u	4 u	3 u
Change				+ 20
After	12 u	2 u	1x4 = 4 u	2x4 = 8 u

Number of pomegranates in Container J remains unchanged.  Make the number of pomegranates in Container J the same.  LCM of 4 and 1 is 4.

Number of lemons put into Container J
= 8 u - 3 u
= 5 u

5 u = 20

1 u = 20 ÷ 5 = 4

Number of fruits in Container H
= 12 u + 2 u
= 14 u
= 14 x 4
= 56

Answer(s): 56