There were some kiwis and chikoos in Box A and Box B. In Box A, the ratio of the kiwis to the number of chikoos was 1 : 1. In Box B, the ratio of the number of kiwis to the number of chikoos was 3 : 1. There were 2 times as many fruits in Box A as in Box B. After another 80 chikoos were put into Box B, the ratio of the number of kiwis to the number of chikoos in Box B became 1 : 3. How many fruits were there in Box A?
Box A |
Box B |
2x4 = 8 u |
1x4 = 4 u |
Kiwis |
Chikoos |
Kiwis |
Chikoos |
1x4 |
1x4 |
3 |
1 |
4 u |
4 u |
3 u |
1 u |
The total number of fruits in Box A is repeated. Make the total number of fruits in Box A the same. LCM of 2 and 2 is 8.
The total number of fruits in Box B at first is repeated. Make the total number of fruits in Box B the same. LCM of 1 and 4 is 4.
|
Box A |
Box B |
|
Kiwis |
Chikoos |
Kiwis |
Chikoos |
Before |
4 u |
4 u |
3 u |
1 u |
Change |
|
|
|
+ 80 |
After
|
4 u
|
4 u
|
1x3 = 3 u |
3x3 = 9 u |
Number of kiwis in Box B remains unchanged. Make the number of kiwis in Box B the same. LCM of 3 and 1 is 3.
Number of chikoos put into Box B
= 9 u - 1 u
= 8 u
8 u = 80
1 u = 80 ÷ 8 = 10
Number of fruits in Box A
= 4 u + 4 u
= 8 u
= 8 x 10
= 80
Answer(s): 80