There were some starfruits and persimmons in Box E and Box F. In Box E, the ratio of the starfruits to the number of persimmons was 11 : 1. In Box F, the ratio of the number of starfruits to the number of persimmons was 5 : 3. There were 3 times as many fruits in Box E as in Box F. After another 70 persimmons were put into Box F, the ratio of the number of starfruits to the number of persimmons in Box F became 1 : 2. How many fruits were there in Box E?

Box E		Box F
3x8 = 24 u		1x8 = 8 u
Starfruits	Persimmons	Starfruits	Persimmons
11x2	1x2	5	3
22 u	2 u	5 u	3 u

The total number of fruits in Box E is repeated.  Make the total number of fruits in Box E the same.  LCM of 3 and 12 is 24.

The total number of fruits in Box F at first is repeated.  Make the total number of fruits in Box F the same.  LCM of 1 and 8 is 8.

	Box E		Box F
	Starfruits	Persimmons	Starfruits	Persimmons
Before	22 u	2 u	5 u	3 u
Change				+ 70
After	22 u	2 u	1x5 = 5 u	2x5 = 10 u

Number of starfruits in Box F remains unchanged.  Make the number of starfruits in Box F the same.  LCM of 5 and 1 is 5.

Number of persimmons put into Box F
= 10 u - 3 u
= 7 u

7 u = 70

1 u = 70 ÷ 7 = 10

Number of fruits in Box E
= 22 u + 2 u
= 24 u
= 24 x 10
= 240

Answer(s): 240