There were some chikoos and oranges in Box H and Box J. In Box H, the ratio of the chikoos to the number of oranges was 6 : 1. In Box J, the ratio of the number of chikoos to the number of oranges was 4 : 3. There were 3 times as many fruits in Box H as in Box J. After another 27 oranges were put into Box J, the ratio of the number of chikoos to the number of oranges in Box J became 1 : 3. How many fruits were there in Box H?
Box H |
Box J |
3x7 = 21 u |
1x7 = 7 u |
Chikoos |
Oranges |
Chikoos |
Oranges |
6x3 |
1x3 |
4 |
3 |
18 u |
3 u |
4 u |
3 u |
The total number of fruits in Box H is repeated. Make the total number of fruits in Box H the same. LCM of 3 and 7 is 21.
The total number of fruits in Box J at first is repeated. Make the total number of fruits in Box J the same. LCM of 1 and 7 is 7.
|
Box H |
Box J |
|
Chikoos |
Oranges |
Chikoos |
Oranges |
Before |
18 u |
3 u |
4 u |
3 u |
Change |
|
|
|
+ 27 |
After
|
18 u
|
3 u
|
1x4 = 4 u |
3x4 = 12 u |
Number of chikoos in Box J remains unchanged. Make the number of chikoos in Box J the same. LCM of 4 and 1 is 4.
Number of oranges put into Box J
= 12 u - 3 u
= 9 u
9 u = 27
1 u = 27 ÷ 9 = 3
Number of fruits in Box H
= 18 u + 3 u
= 21 u
= 21 x 3
= 63
Answer(s): 63