There were some mangosteens and apples in Box S and Box T. In Box S, the ratio of the mangosteens to the number of apples was 2 : 1. In Box T, the ratio of the number of mangosteens to the number of apples was 3 : 1. There were 3 times as many fruits in Box S as in Box T. After another 44 apples were put into Box T, the ratio of the number of mangosteens to the number of apples in Box T became 1 : 4. How many fruits were there in Box T in the end?
Box S |
Box T |
3x4 = 12 u |
1x4 = 4 u |
Mangosteens |
Apples |
Mangosteens |
Apples |
2x4 |
1x4 |
3 |
1 |
8 u |
4 u |
3 u |
1 u |
The total number of fruits in Box S is repeated. Make the total number of fruits in Box S the same. LCM of 3 and 3 is 12.
The total number of fruits in Box T at first is repeated. Make the total number of fruits in Box T the same. LCM of 1 and 4 is 4.
|
Box S |
Box T |
|
Mangosteens |
Apples |
Mangosteens |
Apples |
Before |
8 u |
4 u |
3 u |
1 u |
Change |
|
|
|
+ 44 |
After
|
8 u
|
4 u
|
1x3 = 3 u |
4x3 = 12 u |
Number of mangosteens in Box T remains unchanged. Make the number of mangosteens in Box T the same. LCM of 3 and 1 is 3.
Number of apples put into Box T
= 12 u - 1 u
= 11 u
11 u = 44
1 u = 44 ÷ 11 = 4
Number of fruits in Box T in the end
= 3 u + 12 u
= 15 u
= 15 x 4
= 60
Answer(s): 60