There were some kiwis and pomegranates in Container M and Container N. In Container M, the ratio of the kiwis to the number of pomegranates was 6 : 1. In Container N, the ratio of the number of kiwis to the number of pomegranates was 5 : 2. There were 2 times as many fruits in Container M as in Container N. After another 24 pomegranates were put into Container N, the ratio of the number of kiwis to the number of pomegranates in Container N became 1 : 2. How many fruits were there in Container M?

Container M		Container N
2x7 = 14 u		1x7 = 7 u
Kiwis	Pomegranates	Kiwis	Pomegranates
6x2	1x2	5	2
12 u	2 u	5 u	2 u

The total number of fruits in Container M is repeated.  Make the total number of fruits in Container M the same.  LCM of 2 and 7 is 14.

The total number of fruits in Container N at first is repeated.  Make the total number of fruits in Container N the same.  LCM of 1 and 7 is 7.

	Container M		Container N
	Kiwis	Pomegranates	Kiwis	Pomegranates
Before	12 u	2 u	5 u	2 u
Change				+ 24
After	12 u	2 u	1x5 = 5 u	2x5 = 10 u

Number of kiwis in Container N remains unchanged.  Make the number of kiwis in Container N the same.  LCM of 5 and 1 is 5.

Number of pomegranates put into Container N
= 10 u - 2 u
= 8 u

8 u = 24

1 u = 24 ÷ 8 = 3

Number of fruits in Container M
= 12 u + 2 u
= 14 u
= 14 x 3
= 42

Answer(s): 42