There were some starfruits and pears in Box B and Box C. In Box B, the ratio of the starfruits to the number of pears was 6 : 1. In Box C, the ratio of the number of starfruits to the number of pears was 5 : 2. There were 2 times as many fruits in Box B as in Box C. After another 117 pears were put into Box C, the ratio of the number of starfruits to the number of pears in Box C became 1 : 3. How many fruits were there in Box B?

Box B		Box C
2x7 = 14 u		1x7 = 7 u
Starfruits	Pears	Starfruits	Pears
6x2	1x2	5	2
12 u	2 u	5 u	2 u

The total number of fruits in Box B is repeated.  Make the total number of fruits in Box B the same.  LCM of 2 and 7 is 14.

The total number of fruits in Box C at first is repeated.  Make the total number of fruits in Box C the same.  LCM of 1 and 7 is 7.

	Box B		Box C
	Starfruits	Pears	Starfruits	Pears
Before	12 u	2 u	5 u	2 u
Change				+ 117
After	12 u	2 u	1x5 = 5 u	3x5 = 15 u

Number of starfruits in Box C remains unchanged.  Make the number of starfruits in Box C the same.  LCM of 5 and 1 is 5.

Number of pears put into Box C
= 15 u - 2 u
= 13 u

13 u = 117

1 u = 117 ÷ 13 = 9

Number of fruits in Box B
= 12 u + 2 u
= 14 u
= 14 x 9
= 126

Answer(s): 126