There were some pomegranates and oranges in Container D and Container E. In Container D, the ratio of the pomegranates to the number of oranges was 6 : 1. In Container E, the ratio of the number of pomegranates to the number of oranges was 5 : 2. There were 3 times as many fruits in Container D as in Container E. After another 64 oranges were put into Container E, the ratio of the number of pomegranates to the number of oranges in Container E became 1 : 2. How many fruits were there in Container E in the end?

Container D		Container E
3x7 = 21 u		1x7 = 7 u
Pomegranates	Oranges	Pomegranates	Oranges
6x3	1x3	5	2
18 u	3 u	5 u	2 u

The total number of fruits in Container D is repeated.  Make the total number of fruits in Container D the same.  LCM of 3 and 7 is 21.

The total number of fruits in Container E at first is repeated.  Make the total number of fruits in Container E the same.  LCM of 1 and 7 is 7.

	Container D		Container E
	Pomegranates	Oranges	Pomegranates	Oranges
Before	18 u	3 u	5 u	2 u
Change				+ 64
After	18 u	3 u	1x5 = 5 u	2x5 = 10 u

Number of pomegranates in Container E remains unchanged.  Make the number of pomegranates in Container E the same.  LCM of 5 and 1 is 5.

Number of oranges put into Container E
= 10 u - 2 u
= 8 u

8 u = 64

1 u = 64 ÷ 8 = 8

Number of fruits in Container E in the end
= 5 u + 10 u
= 15 u
= 15 x 8
= 120

Answer(s): 120