There were some chikoos and mangoes in Box S and Box T. In Box S, the ratio of the chikoos to the number of mangoes was 7 : 1. In Box T, the ratio of the number of chikoos to the number of mangoes was 5 : 3. There were 3 times as many fruits in Box S as in Box T. After another 153 mangoes were put into Box T, the ratio of the number of chikoos to the number of mangoes in Box T became 1 : 4. How many fruits were there in Box T in the end?

Box S		Box T
3x8 = 24 u		1x8 = 8 u
Chikoos	Mangoes	Chikoos	Mangoes
7x3	1x3	5	3
21 u	3 u	5 u	3 u

The total number of fruits in Box S is repeated.  Make the total number of fruits in Box S the same.  LCM of 3 and 8 is 24.

The total number of fruits in Box T at first is repeated.  Make the total number of fruits in Box T the same.  LCM of 1 and 8 is 8.

	Box S		Box T
	Chikoos	Mangoes	Chikoos	Mangoes
Before	21 u	3 u	5 u	3 u
Change				+ 153
After	21 u	3 u	1x5 = 5 u	4x5 = 20 u

Number of chikoos in Box T remains unchanged.  Make the number of chikoos in Box T the same.  LCM of 5 and 1 is 5.

Number of mangoes put into Box T
= 20 u - 3 u
= 17 u

17 u = 153

1 u = 153 ÷ 17 = 9

Number of fruits in Box T in the end
= 5 u + 20 u
= 25 u
= 25 x 9
= 225

Answer(s): 225