There were some oranges and pears in Box L and Box M. In Box L, the ratio of the oranges to the number of pears was 4 : 1. In Box M, the ratio of the number of oranges to the number of pears was 3 : 2. There were 3 times as many fruits in Box L as in Box M. After another 16 pears were put into Box M, the ratio of the number of oranges to the number of pears in Box M became 1 : 2. How many fruits were there in Box L?
Box L |
Box M |
3x5 = 15 u |
1x5 = 5 u |
Oranges |
Pears |
Oranges |
Pears |
4x3 |
1x3 |
3 |
2 |
12 u |
3 u |
3 u |
2 u |
The total number of fruits in Box L is repeated. Make the total number of fruits in Box L the same. LCM of 3 and 5 is 15.
The total number of fruits in Box M at first is repeated. Make the total number of fruits in Box M the same. LCM of 1 and 5 is 5.
|
Box L |
Box M |
|
Oranges |
Pears |
Oranges |
Pears |
Before |
12 u |
3 u |
3 u |
2 u |
Change |
|
|
|
+ 16 |
After
|
12 u
|
3 u
|
1x3 = 3 u |
2x3 = 6 u |
Number of oranges in Box M remains unchanged. Make the number of oranges in Box M the same. LCM of 3 and 1 is 3.
Number of pears put into Box M
= 6 u - 2 u
= 4 u
4 u = 16
1 u = 16 ÷ 4 = 4
Number of fruits in Box L
= 12 u + 3 u
= 15 u
= 15 x 4
= 60
Answer(s): 60