There were some persimmons and mangoes in Container V and Container W. In Container V, the ratio of the persimmons to the number of mangoes was 7 : 1. In Container W, the ratio of the number of persimmons to the number of mangoes was 5 : 3. There were 3 times as many fruits in Container V as in Container W. After another 96 mangoes were put into Container W, the ratio of the number of persimmons to the number of mangoes in Container W became 1 : 3. How many fruits were there in Container V?
Container V |
Container W |
3x8 = 24 u |
1x8 = 8 u |
Persimmons |
Mangoes |
Persimmons |
Mangoes |
7x3 |
1x3 |
5 |
3 |
21 u |
3 u |
5 u |
3 u |
The total number of fruits in Container V is repeated. Make the total number of fruits in Container V the same. LCM of 3 and 8 is 24.
The total number of fruits in Container W at first is repeated. Make the total number of fruits in Container W the same. LCM of 1 and 8 is 8.
|
Container V |
Container W |
|
Persimmons |
Mangoes |
Persimmons |
Mangoes |
Before |
21 u |
3 u |
5 u |
3 u |
Change |
|
|
|
+ 96 |
After
|
21 u
|
3 u
|
1x5 = 5 u |
3x5 = 15 u |
Number of persimmons in Container W remains unchanged. Make the number of persimmons in Container W the same. LCM of 5 and 1 is 5.
Number of mangoes put into Container W
= 15 u - 3 u
= 12 u
12 u = 96
1 u = 96 ÷ 12 = 8
Number of fruits in Container V
= 21 u + 3 u
= 24 u
= 24 x 8
= 192
Answer(s): 192