There were some kiwis and lemons in Box X and Box Y. In Box X, the ratio of the kiwis to the number of lemons was 6 : 1. In Box Y, the ratio of the number of kiwis to the number of lemons was 4 : 3. There were 2 times as many fruits in Box X as in Box Y. After another 63 lemons were put into Box Y, the ratio of the number of kiwis to the number of lemons in Box Y became 1 : 3. How many fruits were there in Box Y in the end?

Box X		Box Y
2x7 = 14 u		1x7 = 7 u
Kiwis	Lemons	Kiwis	Lemons
6x2	1x2	4	3
12 u	2 u	4 u	3 u

The total number of fruits in Box X is repeated.  Make the total number of fruits in Box X the same.  LCM of 2 and 7 is 14.

The total number of fruits in Box Y at first is repeated.  Make the total number of fruits in Box Y the same.  LCM of 1 and 7 is 7.

	Box X		Box Y
	Kiwis	Lemons	Kiwis	Lemons
Before	12 u	2 u	4 u	3 u
Change				+ 63
After	12 u	2 u	1x4 = 4 u	3x4 = 12 u

Number of kiwis in Box Y remains unchanged.  Make the number of kiwis in Box Y the same.  LCM of 4 and 1 is 4.

Number of lemons put into Box Y
= 12 u - 3 u
= 9 u

9 u = 63

1 u = 63 ÷ 9 = 7

Number of fruits in Box Y in the end
= 4 u + 12 u
= 16 u
= 16 x 7
= 112

Answer(s): 112