There were some passion fruits and pears in Container D and Container E. In Container D, the ratio of the passion fruits to the number of pears was 6 : 1. In Container E, the ratio of the number of passion fruits to the number of pears was 5 : 2. There were 2 times as many fruits in Container D as in Container E. After another 39 pears were put into Container E, the ratio of the number of passion fruits to the number of pears in Container E became 1 : 3. How many fruits were there in Container D?
Container D |
Container E |
2x7 = 14 u |
1x7 = 7 u |
Passion fruits |
Pears |
Passion fruits |
Pears |
6x2 |
1x2 |
5 |
2 |
12 u |
2 u |
5 u |
2 u |
The total number of fruits in Container D is repeated. Make the total number of fruits in Container D the same. LCM of 2 and 7 is 14.
The total number of fruits in Container E at first is repeated. Make the total number of fruits in Container E the same. LCM of 1 and 7 is 7.
|
Container D |
Container E |
|
Passion fruits |
Pears |
Passion fruits |
Pears |
Before |
12 u |
2 u |
5 u |
2 u |
Change |
|
|
|
+ 39 |
After
|
12 u
|
2 u
|
1x5 = 5 u |
3x5 = 15 u |
Number of passion fruits in Container E remains unchanged. Make the number of passion fruits in Container E the same. LCM of 5 and 1 is 5.
Number of pears put into Container E
= 15 u - 2 u
= 13 u
13 u = 39
1 u = 39 ÷ 13 = 3
Number of fruits in Container D
= 12 u + 2 u
= 14 u
= 14 x 3
= 42
Answer(s): 42