There were some pomegranates and apples in Box G and Box H. In Box G, the ratio of the pomegranates to the number of apples was 3 : 1. In Box H, the ratio of the number of pomegranates to the number of apples was 3 : 1. There were 2 times as many fruits in Box G as in Box H. After another 110 apples were put into Box H, the ratio of the number of pomegranates to the number of apples in Box H became 1 : 4. How many fruits were there in Box H in the end?
Box G |
Box H |
2x4 = 8 u |
1x4 = 4 u |
Pomegranates |
Apples |
Pomegranates |
Apples |
3x2 |
1x2 |
3 |
1 |
6 u |
2 u |
3 u |
1 u |
The total number of fruits in Box G is repeated. Make the total number of fruits in Box G the same. LCM of 2 and 4 is 8.
The total number of fruits in Box H at first is repeated. Make the total number of fruits in Box H the same. LCM of 1 and 4 is 4.
|
Box G |
Box H |
|
Pomegranates |
Apples |
Pomegranates |
Apples |
Before |
6 u |
2 u |
3 u |
1 u |
Change |
|
|
|
+ 110 |
After
|
6 u
|
2 u
|
1x3 = 3 u |
4x3 = 12 u |
Number of pomegranates in Box H remains unchanged. Make the number of pomegranates in Box H the same. LCM of 3 and 1 is 3.
Number of apples put into Box H
= 12 u - 1 u
= 11 u
11 u = 110
1 u = 110 ÷ 11 = 10
Number of fruits in Box H in the end
= 3 u + 12 u
= 15 u
= 15 x 10
= 150
Answer(s): 150