There were some chikoos and pomegranates in Box M and Box N. In Box M, the ratio of the chikoos to the number of pomegranates was 2 : 1. In Box N, the ratio of the number of chikoos to the number of pomegranates was 3 : 1. There were 3 times as many fruits in Box M as in Box N. After another 72 pomegranates were put into Box N, the ratio of the number of chikoos to the number of pomegranates in Box N became 1 : 3. How many fruits were there in Box N in the end?
Box M |
Box N |
3x4 = 12 u |
1x4 = 4 u |
Chikoos |
Pomegranates |
Chikoos |
Pomegranates |
2x4 |
1x4 |
3 |
1 |
8 u |
4 u |
3 u |
1 u |
The total number of fruits in Box M is repeated. Make the total number of fruits in Box M the same. LCM of 3 and 3 is 12.
The total number of fruits in Box N at first is repeated. Make the total number of fruits in Box N the same. LCM of 1 and 4 is 4.
|
Box M |
Box N |
|
Chikoos |
Pomegranates |
Chikoos |
Pomegranates |
Before |
8 u |
4 u |
3 u |
1 u |
Change |
|
|
|
+ 72 |
After
|
8 u
|
4 u
|
1x3 = 3 u |
3x3 = 9 u |
Number of chikoos in Box N remains unchanged. Make the number of chikoos in Box N the same. LCM of 3 and 1 is 3.
Number of pomegranates put into Box N
= 9 u - 1 u
= 8 u
8 u = 72
1 u = 72 ÷ 8 = 9
Number of fruits in Box N in the end
= 3 u + 9 u
= 12 u
= 12 x 9
= 108
Answer(s): 108