There were some chikoos and persimmons in Container G and Container H. In Container G, the ratio of the chikoos to the number of persimmons was 1 : 1. In Container H, the ratio of the number of chikoos to the number of persimmons was 3 : 1. There were 2 times as many fruits in Container G as in Container H. After another 55 persimmons were put into Container H, the ratio of the number of chikoos to the number of persimmons in Container H became 1 : 4. How many fruits were there in Container H in the end?
Container G |
Container H |
2x4 = 8 u |
1x4 = 4 u |
Chikoos |
Persimmons |
Chikoos |
Persimmons |
1x4 |
1x4 |
3 |
1 |
4 u |
4 u |
3 u |
1 u |
The total number of fruits in Container G is repeated. Make the total number of fruits in Container G the same. LCM of 2 and 2 is 8.
The total number of fruits in Container H at first is repeated. Make the total number of fruits in Container H the same. LCM of 1 and 4 is 4.
|
Container G |
Container H |
|
Chikoos |
Persimmons |
Chikoos |
Persimmons |
Before |
4 u |
4 u |
3 u |
1 u |
Change |
|
|
|
+ 55 |
After
|
4 u
|
4 u
|
1x3 = 3 u |
4x3 = 12 u |
Number of chikoos in Container H remains unchanged. Make the number of chikoos in Container H the same. LCM of 3 and 1 is 3.
Number of persimmons put into Container H
= 12 u - 1 u
= 11 u
11 u = 55
1 u = 55 ÷ 11 = 5
Number of fruits in Container H in the end
= 3 u + 12 u
= 15 u
= 15 x 5
= 75
Answer(s): 75