There were some pomegranates and kiwis in Container T and Container U. In Container T, the ratio of the pomegranates to the number of kiwis was 2 : 1. In Container U, the ratio of the number of pomegranates to the number of kiwis was 3 : 1. There were 3 times as many fruits in Container T as in Container U. After another 16 kiwis were put into Container U, the ratio of the number of pomegranates to the number of kiwis in Container U became 1 : 3. How many fruits were there in Container T?

Container T		Container U
3x4 = 12 u		1x4 = 4 u
Pomegranates	Kiwis	Pomegranates	Kiwis
2x4	1x4	3	1
8 u	4 u	3 u	1 u

The total number of fruits in Container T is repeated.  Make the total number of fruits in Container T the same.  LCM of 3 and 3 is 12.

The total number of fruits in Container U at first is repeated.  Make the total number of fruits in Container U the same.  LCM of 1 and 4 is 4.

	Container T		Container U
	Pomegranates	Kiwis	Pomegranates	Kiwis
Before	8 u	4 u	3 u	1 u
Change				+ 16
After	8 u	4 u	1x3 = 3 u	3x3 = 9 u

Number of pomegranates in Container U remains unchanged.  Make the number of pomegranates in Container U the same.  LCM of 3 and 1 is 3.

Number of kiwis put into Container U
= 9 u - 1 u
= 8 u

8 u = 16

1 u = 16 ÷ 8 = 2

Number of fruits in Container T
= 8 u + 4 u
= 12 u
= 12 x 2
= 24

Answer(s): 24