There were some mangosteens and lemons in Box G and Box H. In Box G, the ratio of the mangosteens to the number of lemons was 6 : 1. In Box H, the ratio of the number of mangosteens to the number of lemons was 4 : 3. There were 2 times as many fruits in Box G as in Box H. After another 10 lemons were put into Box H, the ratio of the number of mangosteens to the number of lemons in Box H became 1 : 2. How many fruits were there in Box H in the end?
Box G |
Box H |
2x7 = 14 u |
1x7 = 7 u |
Mangosteens |
Lemons |
Mangosteens |
Lemons |
6x2 |
1x2 |
4 |
3 |
12 u |
2 u |
4 u |
3 u |
The total number of fruits in Box G is repeated. Make the total number of fruits in Box G the same. LCM of 2 and 7 is 14.
The total number of fruits in Box H at first is repeated. Make the total number of fruits in Box H the same. LCM of 1 and 7 is 7.
|
Box G |
Box H |
|
Mangosteens |
Lemons |
Mangosteens |
Lemons |
Before |
12 u |
2 u |
4 u |
3 u |
Change |
|
|
|
+ 10 |
After
|
12 u
|
2 u
|
1x4 = 4 u |
2x4 = 8 u |
Number of mangosteens in Box H remains unchanged. Make the number of mangosteens in Box H the same. LCM of 4 and 1 is 4.
Number of lemons put into Box H
= 8 u - 3 u
= 5 u
5 u = 10
1 u = 10 ÷ 5 = 2
Number of fruits in Box H in the end
= 4 u + 8 u
= 12 u
= 12 x 2
= 24
Answer(s): 24