There were some oranges and mangosteens in Container M and Container N. In Container M, the ratio of the oranges to the number of mangosteens was 6 : 1. In Container N, the ratio of the number of oranges to the number of mangosteens was 5 : 2. There were 3 times as many fruits in Container M as in Container N. After another 90 mangosteens were put into Container N, the ratio of the number of oranges to the number of mangosteens in Container N became 1 : 4. How many fruits were there in Container M?
Container M |
Container N |
3x7 = 21 u |
1x7 = 7 u |
Oranges |
Mangosteens |
Oranges |
Mangosteens |
6x3 |
1x3 |
5 |
2 |
18 u |
3 u |
5 u |
2 u |
The total number of fruits in Container M is repeated. Make the total number of fruits in Container M the same. LCM of 3 and 7 is 21.
The total number of fruits in Container N at first is repeated. Make the total number of fruits in Container N the same. LCM of 1 and 7 is 7.
|
Container M |
Container N |
|
Oranges |
Mangosteens |
Oranges |
Mangosteens |
Before |
18 u |
3 u |
5 u |
2 u |
Change |
|
|
|
+ 90 |
After
|
18 u
|
3 u
|
1x5 = 5 u |
4x5 = 20 u |
Number of oranges in Container N remains unchanged. Make the number of oranges in Container N the same. LCM of 5 and 1 is 5.
Number of mangosteens put into Container N
= 20 u - 2 u
= 18 u
18 u = 90
1 u = 90 ÷ 18 = 5
Number of fruits in Container M
= 18 u + 3 u
= 21 u
= 21 x 5
= 105
Answer(s): 105