There were some persimmons and passion fruits in Container E and Container F. In Container E, the ratio of the persimmons to the number of passion fruits was 6 : 1. In Container F, the ratio of the number of persimmons to the number of passion fruits was 4 : 3. There were 2 times as many fruits in Container E as in Container F. After another 36 passion fruits were put into Container F, the ratio of the number of persimmons to the number of passion fruits in Container F became 1 : 3. How many fruits were there in Container F in the end?
Container E |
Container F |
2x7 = 14 u |
1x7 = 7 u |
Persimmons |
Passion fruits |
Persimmons |
Passion fruits |
6x2 |
1x2 |
4 |
3 |
12 u |
2 u |
4 u |
3 u |
The total number of fruits in Container E is repeated. Make the total number of fruits in Container E the same. LCM of 2 and 7 is 14.
The total number of fruits in Container F at first is repeated. Make the total number of fruits in Container F the same. LCM of 1 and 7 is 7.
|
Container E |
Container F |
|
Persimmons |
Passion fruits |
Persimmons |
Passion fruits |
Before |
12 u |
2 u |
4 u |
3 u |
Change |
|
|
|
+ 36 |
After
|
12 u
|
2 u
|
1x4 = 4 u |
3x4 = 12 u |
Number of persimmons in Container F remains unchanged. Make the number of persimmons in Container F the same. LCM of 4 and 1 is 4.
Number of passion fruits put into Container F
= 12 u - 3 u
= 9 u
9 u = 36
1 u = 36 ÷ 9 = 4
Number of fruits in Container F in the end
= 4 u + 12 u
= 16 u
= 16 x 4
= 64
Answer(s): 64