There were some oranges and mangoes in Container N and Container P. In Container N, the ratio of the oranges to the number of mangoes was 1 : 1. In Container P, the ratio of the number of oranges to the number of mangoes was 3 : 1. There were 2 times as many fruits in Container N as in Container P. After another 10 mangoes were put into Container P, the ratio of the number of oranges to the number of mangoes in Container P became 1 : 2. How many fruits were there in Container P in the end?

Container N		Container P
2x4 = 8 u		1x4 = 4 u
Oranges	Mangoes	Oranges	Mangoes
1x4	1x4	3	1
4 u	4 u	3 u	1 u

The total number of fruits in Container N is repeated.  Make the total number of fruits in Container N the same.  LCM of 2 and 2 is 8.

The total number of fruits in Container P at first is repeated.  Make the total number of fruits in Container P the same.  LCM of 1 and 4 is 4.

	Container N		Container P
	Oranges	Mangoes	Oranges	Mangoes
Before	4 u	4 u	3 u	1 u
Change				+ 10
After	4 u	4 u	1x3 = 3 u	2x3 = 6 u

Number of oranges in Container P remains unchanged.  Make the number of oranges in Container P the same.  LCM of 3 and 1 is 3.

Number of mangoes put into Container P
= 6 u - 1 u
= 5 u

5 u = 10

1 u = 10 ÷ 5 = 2

Number of fruits in Container P in the end
= 3 u + 6 u
= 9 u
= 9 x 2
= 18

Answer(s): 18