There were some lemons and chikoos in Box A and Box B. In Box A, the ratio of the lemons to the number of chikoos was 6 : 1. In Box B, the ratio of the number of lemons to the number of chikoos was 5 : 2. There were 2 times as many fruits in Box A as in Box B. After another 108 chikoos were put into Box B, the ratio of the number of lemons to the number of chikoos in Box B became 1 : 4. How many fruits were there in Box B in the end?

Box A		Box B
2x7 = 14 u		1x7 = 7 u
Lemons	Chikoos	Lemons	Chikoos
6x2	1x2	5	2
12 u	2 u	5 u	2 u

The total number of fruits in Box A is repeated.  Make the total number of fruits in Box A the same.  LCM of 2 and 7 is 14.

The total number of fruits in Box B at first is repeated.  Make the total number of fruits in Box B the same.  LCM of 1 and 7 is 7.

	Box A		Box B
	Lemons	Chikoos	Lemons	Chikoos
Before	12 u	2 u	5 u	2 u
Change				+ 108
After	12 u	2 u	1x5 = 5 u	4x5 = 20 u

Number of lemons in Box B remains unchanged.  Make the number of lemons in Box B the same.  LCM of 5 and 1 is 5.

Number of chikoos put into Box B
= 20 u - 2 u
= 18 u

18 u = 108

1 u = 108 ÷ 18 = 6

Number of fruits in Box B in the end
= 5 u + 20 u
= 25 u
= 25 x 6
= 150

Answer(s): 150