There were some pomegranates and pears in Box G and Box H. In Box G, the ratio of the pomegranates to the number of pears was 6 : 1. In Box H, the ratio of the number of pomegranates to the number of pears was 4 : 3. There were 3 times as many fruits in Box G as in Box H. After another 130 pears were put into Box H, the ratio of the number of pomegranates to the number of pears in Box H became 1 : 4. How many fruits were there in Box H in the end?

Box G		Box H
3x7 = 21 u		1x7 = 7 u
Pomegranates	Pears	Pomegranates	Pears
6x3	1x3	4	3
18 u	3 u	4 u	3 u

The total number of fruits in Box G is repeated.  Make the total number of fruits in Box G the same.  LCM of 3 and 7 is 21.

The total number of fruits in Box H at first is repeated.  Make the total number of fruits in Box H the same.  LCM of 1 and 7 is 7.

	Box G		Box H
	Pomegranates	Pears	Pomegranates	Pears
Before	18 u	3 u	4 u	3 u
Change				+ 130
After	18 u	3 u	1x4 = 4 u	4x4 = 16 u

Number of pomegranates in Box H remains unchanged.  Make the number of pomegranates in Box H the same.  LCM of 4 and 1 is 4.

Number of pears put into Box H
= 16 u - 3 u
= 13 u

13 u = 130

1 u = 130 ÷ 13 = 10

Number of fruits in Box H in the end
= 4 u + 16 u
= 20 u
= 20 x 10
= 200

Answer(s): 200