There were some apples and chikoos in Container D and Container E. In Container D, the ratio of the apples to the number of chikoos was 5 : 1. In Container E, the ratio of the number of apples to the number of chikoos was 5 : 3. There were 3 times as many fruits in Container D as in Container E. After another 170 chikoos were put into Container E, the ratio of the number of apples to the number of chikoos in Container E became 1 : 4. How many fruits were there in Container D?

Container D		Container E
3x8 = 24 u		1x8 = 8 u
Apples	Chikoos	Apples	Chikoos
5x4	1x4	5	3
20 u	4 u	5 u	3 u

The total number of fruits in Container D is repeated.  Make the total number of fruits in Container D the same.  LCM of 3 and 6 is 24.

The total number of fruits in Container E at first is repeated.  Make the total number of fruits in Container E the same.  LCM of 1 and 8 is 8.

	Container D		Container E
	Apples	Chikoos	Apples	Chikoos
Before	20 u	4 u	5 u	3 u
Change				+ 170
After	20 u	4 u	1x5 = 5 u	4x5 = 20 u

Number of apples in Container E remains unchanged.  Make the number of apples in Container E the same.  LCM of 5 and 1 is 5.

Number of chikoos put into Container E
= 20 u - 3 u
= 17 u

17 u = 170

1 u = 170 ÷ 17 = 10

Number of fruits in Container D
= 20 u + 4 u
= 24 u
= 24 x 10
= 240

Answer(s): 240