There were some apples and passion fruits in Container X and Container Y. In Container X, the ratio of the apples to the number of passion fruits was 5 : 1. In Container Y, the ratio of the number of apples to the number of passion fruits was 3 : 1. There were 3 times as many fruits in Container X as in Container Y. After another 72 passion fruits were put into Container Y, the ratio of the number of apples to the number of passion fruits in Container Y became 1 : 3. How many fruits were there in Container Y in the end?
Container X |
Container Y |
3x4 = 12 u |
1x4 = 4 u |
Apples |
Passion fruits |
Apples |
Passion fruits |
5x2 |
1x2 |
3 |
1 |
10 u |
2 u |
3 u |
1 u |
The total number of fruits in Container X is repeated. Make the total number of fruits in Container X the same. LCM of 3 and 6 is 12.
The total number of fruits in Container Y at first is repeated. Make the total number of fruits in Container Y the same. LCM of 1 and 4 is 4.
|
Container X |
Container Y |
|
Apples |
Passion fruits |
Apples |
Passion fruits |
Before |
10 u |
2 u |
3 u |
1 u |
Change |
|
|
|
+ 72 |
After
|
10 u
|
2 u
|
1x3 = 3 u |
3x3 = 9 u |
Number of apples in Container Y remains unchanged. Make the number of apples in Container Y the same. LCM of 3 and 1 is 3.
Number of passion fruits put into Container Y
= 9 u - 1 u
= 8 u
8 u = 72
1 u = 72 ÷ 8 = 9
Number of fruits in Container Y in the end
= 3 u + 9 u
= 12 u
= 12 x 9
= 108
Answer(s): 108