There were some apples and pears in Box E and Box F. In Box E, the ratio of the apples to the number of pears was 5 : 1. In Box F, the ratio of the number of apples to the number of pears was 5 : 3. There were 3 times as many fruits in Box E as in Box F. After another 85 pears were put into Box F, the ratio of the number of apples to the number of pears in Box F became 1 : 4. How many fruits were there in Box F in the end?

Box E		Box F
3x8 = 24 u		1x8 = 8 u
Apples	Pears	Apples	Pears
5x4	1x4	5	3
20 u	4 u	5 u	3 u

The total number of fruits in Box E is repeated.  Make the total number of fruits in Box E the same.  LCM of 3 and 6 is 24.

The total number of fruits in Box F at first is repeated.  Make the total number of fruits in Box F the same.  LCM of 1 and 8 is 8.

	Box E		Box F
	Apples	Pears	Apples	Pears
Before	20 u	4 u	5 u	3 u
Change				+ 85
After	20 u	4 u	1x5 = 5 u	4x5 = 20 u

Number of apples in Box F remains unchanged.  Make the number of apples in Box F the same.  LCM of 5 and 1 is 5.

Number of pears put into Box F
= 20 u - 3 u
= 17 u

17 u = 85

1 u = 85 ÷ 17 = 5

Number of fruits in Box F in the end
= 5 u + 20 u
= 25 u
= 25 x 5
= 125

Answer(s): 125