There were some lemons and starfruits in Container U and Container V. In Container U, the ratio of the lemons to the number of starfruits was 3 : 1. In Container V, the ratio of the number of lemons to the number of starfruits was 3 : 1. There were 3 times as many fruits in Container U as in Container V. After another 35 starfruits were put into Container V, the ratio of the number of lemons to the number of starfruits in Container V became 1 : 2. How many fruits were there in Container U?
Container U |
Container V |
3x4 = 12 u |
1x4 = 4 u |
Lemons |
Starfruits |
Lemons |
Starfruits |
3x3 |
1x3 |
3 |
1 |
9 u |
3 u |
3 u |
1 u |
The total number of fruits in Container U is repeated. Make the total number of fruits in Container U the same. LCM of 3 and 4 is 12.
The total number of fruits in Container V at first is repeated. Make the total number of fruits in Container V the same. LCM of 1 and 4 is 4.
|
Container U |
Container V |
|
Lemons |
Starfruits |
Lemons |
Starfruits |
Before |
9 u |
3 u |
3 u |
1 u |
Change |
|
|
|
+ 35 |
After
|
9 u
|
3 u
|
1x3 = 3 u |
2x3 = 6 u |
Number of lemons in Container V remains unchanged. Make the number of lemons in Container V the same. LCM of 3 and 1 is 3.
Number of starfruits put into Container V
= 6 u - 1 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Number of fruits in Container U
= 9 u + 3 u
= 12 u
= 12 x 7
= 84
Answer(s): 84