There were some kiwis and pomegranates in Container A and Container B. In Container A, the ratio of the kiwis to the number of pomegranates was 11 : 1. In Container B, the ratio of the number of kiwis to the number of pomegranates was 5 : 3. There were 3 times as many fruits in Container A as in Container B. After another 153 pomegranates were put into Container B, the ratio of the number of kiwis to the number of pomegranates in Container B became 1 : 4. How many fruits were there in Container A?

Container A		Container B
3x8 = 24 u		1x8 = 8 u
Kiwis	Pomegranates	Kiwis	Pomegranates
11x2	1x2	5	3
22 u	2 u	5 u	3 u

The total number of fruits in Container A is repeated.  Make the total number of fruits in Container A the same.  LCM of 3 and 12 is 24.

The total number of fruits in Container B at first is repeated.  Make the total number of fruits in Container B the same.  LCM of 1 and 8 is 8.

	Container A		Container B
	Kiwis	Pomegranates	Kiwis	Pomegranates
Before	22 u	2 u	5 u	3 u
Change				+ 153
After	22 u	2 u	1x5 = 5 u	4x5 = 20 u

Number of kiwis in Container B remains unchanged.  Make the number of kiwis in Container B the same.  LCM of 5 and 1 is 5.

Number of pomegranates put into Container B
= 20 u - 3 u
= 17 u

17 u = 153

1 u = 153 ÷ 17 = 9

Number of fruits in Container A
= 22 u + 2 u
= 24 u
= 24 x 9
= 216

Answer(s): 216