There were some mangoes and chikoos in Container A and Container B. In Container A, the ratio of the mangoes to the number of chikoos was 7 : 1. In Container B, the ratio of the number of mangoes to the number of chikoos was 5 : 3. There were 2 times as many fruits in Container A as in Container B. After another 36 chikoos were put into Container B, the ratio of the number of mangoes to the number of chikoos in Container B became 1 : 3. How many fruits were there in Container B in the end?

Container A		Container B
2x8 = 16 u		1x8 = 8 u
Mangoes	Chikoos	Mangoes	Chikoos
7x2	1x2	5	3
14 u	2 u	5 u	3 u

The total number of fruits in Container A is repeated.  Make the total number of fruits in Container A the same.  LCM of 2 and 8 is 16.

The total number of fruits in Container B at first is repeated.  Make the total number of fruits in Container B the same.  LCM of 1 and 8 is 8.

	Container A		Container B
	Mangoes	Chikoos	Mangoes	Chikoos
Before	14 u	2 u	5 u	3 u
Change				+ 36
After	14 u	2 u	1x5 = 5 u	3x5 = 15 u

Number of mangoes in Container B remains unchanged.  Make the number of mangoes in Container B the same.  LCM of 5 and 1 is 5.

Number of chikoos put into Container B
= 15 u - 3 u
= 12 u

12 u = 36

1 u = 36 ÷ 12 = 3

Number of fruits in Container B in the end
= 5 u + 15 u
= 20 u
= 20 x 3
= 60

Answer(s): 60