There were some persimmons and starfruits in Container M and Container N. In Container M, the ratio of the persimmons to the number of starfruits was 6 : 1. In Container N, the ratio of the number of persimmons to the number of starfruits was 4 : 3. There were 3 times as many fruits in Container M as in Container N. After another 45 starfruits were put into Container N, the ratio of the number of persimmons to the number of starfruits in Container N became 1 : 2. How many fruits were there in Container M?

Container M		Container N
3x7 = 21 u		1x7 = 7 u
Persimmons	Starfruits	Persimmons	Starfruits
6x3	1x3	4	3
18 u	3 u	4 u	3 u

The total number of fruits in Container M is repeated.  Make the total number of fruits in Container M the same.  LCM of 3 and 7 is 21.

The total number of fruits in Container N at first is repeated.  Make the total number of fruits in Container N the same.  LCM of 1 and 7 is 7.

	Container M		Container N
	Persimmons	Starfruits	Persimmons	Starfruits
Before	18 u	3 u	4 u	3 u
Change				+ 45
After	18 u	3 u	1x4 = 4 u	2x4 = 8 u

Number of persimmons in Container N remains unchanged.  Make the number of persimmons in Container N the same.  LCM of 4 and 1 is 4.

Number of starfruits put into Container N
= 8 u - 3 u
= 5 u

5 u = 45

1 u = 45 ÷ 5 = 9

Number of fruits in Container M
= 18 u + 3 u
= 21 u
= 21 x 9
= 189

Answer(s): 189