There were some lemons and pomegranates in Container P and Container Q. In Container P, the ratio of the lemons to the number of pomegranates was 5 : 1. In Container Q, the ratio of the number of lemons to the number of pomegranates was 3 : 1. There were 3 times as many fruits in Container P as in Container Q. After another 15 pomegranates were put into Container Q, the ratio of the number of lemons to the number of pomegranates in Container Q became 1 : 2. How many fruits were there in Container Q in the end?

Container P		Container Q
3x4 = 12 u		1x4 = 4 u
Lemons	Pomegranates	Lemons	Pomegranates
5x2	1x2	3	1
10 u	2 u	3 u	1 u

The total number of fruits in Container P is repeated.  Make the total number of fruits in Container P the same.  LCM of 3 and 6 is 12.

The total number of fruits in Container Q at first is repeated.  Make the total number of fruits in Container Q the same.  LCM of 1 and 4 is 4.

	Container P		Container Q
	Lemons	Pomegranates	Lemons	Pomegranates
Before	10 u	2 u	3 u	1 u
Change				+ 15
After	10 u	2 u	1x3 = 3 u	2x3 = 6 u

Number of lemons in Container Q remains unchanged.  Make the number of lemons in Container Q the same.  LCM of 3 and 1 is 3.

Number of pomegranates put into Container Q
= 6 u - 1 u
= 5 u

5 u = 15

1 u = 15 ÷ 5 = 3

Number of fruits in Container Q in the end
= 3 u + 6 u
= 9 u
= 9 x 3
= 27

Answer(s): 27