There were some chikoos and passion fruits in Container A and Container B. In Container A, the ratio of the chikoos to the number of passion fruits was 5 : 1. In Container B, the ratio of the number of chikoos to the number of passion fruits was 5 : 3. There were 3 times as many fruits in Container A as in Container B. After another 60 passion fruits were put into Container B, the ratio of the number of chikoos to the number of passion fruits in Container B became 1 : 3. How many fruits were there in Container B in the end?

Container A		Container B
3x8 = 24 u		1x8 = 8 u
Chikoos	Passion fruits	Chikoos	Passion fruits
5x4	1x4	5	3
20 u	4 u	5 u	3 u

The total number of fruits in Container A is repeated.  Make the total number of fruits in Container A the same.  LCM of 3 and 6 is 24.

The total number of fruits in Container B at first is repeated.  Make the total number of fruits in Container B the same.  LCM of 1 and 8 is 8.

	Container A		Container B
	Chikoos	Passion fruits	Chikoos	Passion fruits
Before	20 u	4 u	5 u	3 u
Change				+ 60
After	20 u	4 u	1x5 = 5 u	3x5 = 15 u

Number of chikoos in Container B remains unchanged.  Make the number of chikoos in Container B the same.  LCM of 5 and 1 is 5.

Number of passion fruits put into Container B
= 15 u - 3 u
= 12 u

12 u = 60

1 u = 60 ÷ 12 = 5

Number of fruits in Container B in the end
= 5 u + 15 u
= 20 u
= 20 x 5
= 100

Answer(s): 100