There were some mangosteens and persimmons in Box B and Box C. In Box B, the ratio of the mangosteens to the number of persimmons was 3 : 1. In Box C, the ratio of the number of mangosteens to the number of persimmons was 3 : 1. There were 3 times as many fruits in Box B as in Box C. After another 64 persimmons were put into Box C, the ratio of the number of mangosteens to the number of persimmons in Box C became 1 : 3. How many fruits were there in Box C in the end?
Box B |
Box C |
3x4 = 12 u |
1x4 = 4 u |
Mangosteens |
Persimmons |
Mangosteens |
Persimmons |
3x3 |
1x3 |
3 |
1 |
9 u |
3 u |
3 u |
1 u |
The total number of fruits in Box B is repeated. Make the total number of fruits in Box B the same. LCM of 3 and 4 is 12.
The total number of fruits in Box C at first is repeated. Make the total number of fruits in Box C the same. LCM of 1 and 4 is 4.
|
Box B |
Box C |
|
Mangosteens |
Persimmons |
Mangosteens |
Persimmons |
Before |
9 u |
3 u |
3 u |
1 u |
Change |
|
|
|
+ 64 |
After
|
9 u
|
3 u
|
1x3 = 3 u |
3x3 = 9 u |
Number of mangosteens in Box C remains unchanged. Make the number of mangosteens in Box C the same. LCM of 3 and 1 is 3.
Number of persimmons put into Box C
= 9 u - 1 u
= 8 u
8 u = 64
1 u = 64 ÷ 8 = 8
Number of fruits in Box C in the end
= 3 u + 9 u
= 12 u
= 12 x 8
= 96
Answer(s): 96