There were some pomegranates and mangoes in Box R and Box S. In Box R, the ratio of the pomegranates to the number of mangoes was 4 : 1. In Box S, the ratio of the number of pomegranates to the number of mangoes was 3 : 2. There were 2 times as many fruits in Box R as in Box S. After another 24 mangoes were put into Box S, the ratio of the number of pomegranates to the number of mangoes in Box S became 1 : 2. How many fruits were there in Box S in the end?
| Box R |
Box S |
2x5 =
10 u |
1x5 =
5 u |
| Pomegranates |
Mangoes |
Pomegranates |
Mangoes |
| 4x2 |
1x2 |
3 |
2 |
| 8 u |
2 u |
3 u |
2 u |
The total number of fruits in Box R is repeated. Make the total number of fruits in Box R the same. LCM of 2 and 5 is 10.
The total number of fruits in Box S at first is repeated. Make the total number of fruits in Box S the same. LCM of 1 and 5 is 5.
| |
Box R |
Box S |
| |
Pomegranates |
Mangoes |
Pomegranates |
Mangoes |
| Before |
8 u |
2 u |
3 u |
2 u |
| Change |
|
|
|
+ 24 |
After
|
8 u
|
2 u
|
1x3 =
3 u |
2x3 =
6 u |
Number of pomegranates in Box S remains unchanged. Make the number of pomegranates in Box S the same. LCM of 3 and 1 is 3.
Number of mangoes put into Box S
= 6 u - 2 u
= 4 u
4 u = 24
1 u = 24 ÷ 4 = 6
Number of fruits in Box S in the end
= 3 u + 6 u
= 9 u
= 9 x 6
= 54
Answer(s): 54
