There were some pears and persimmons in Container S and Container T. In Container S, the ratio of the pears to the number of persimmons was 7 : 1. In Container T, the ratio of the number of pears to the number of persimmons was 5 : 3. There were 2 times as many fruits in Container S as in Container T. After another 63 persimmons were put into Container T, the ratio of the number of pears to the number of persimmons in Container T became 1 : 2. How many fruits were there in Container S?

Container S		Container T
2x8 = 16 u		1x8 = 8 u
Pears	Persimmons	Pears	Persimmons
7x2	1x2	5	3
14 u	2 u	5 u	3 u

The total number of fruits in Container S is repeated.  Make the total number of fruits in Container S the same.  LCM of 2 and 8 is 16.

The total number of fruits in Container T at first is repeated.  Make the total number of fruits in Container T the same.  LCM of 1 and 8 is 8.

	Container S		Container T
	Pears	Persimmons	Pears	Persimmons
Before	14 u	2 u	5 u	3 u
Change				+ 63
After	14 u	2 u	1x5 = 5 u	2x5 = 10 u

Number of pears in Container T remains unchanged.  Make the number of pears in Container T the same.  LCM of 5 and 1 is 5.

Number of persimmons put into Container T
= 10 u - 3 u
= 7 u

7 u = 63

1 u = 63 ÷ 7 = 9

Number of fruits in Container S
= 14 u + 2 u
= 16 u
= 16 x 9
= 144

Answer(s): 144