A jar contained $20 and $5 notes with a total value of $900. 8 pieces of $5 were exchanged for $20 notes of similar value. In the end, the number of $20 notes was the same as the $5 notes. How many $5 notes were there at first?
| |
$20 |
$5 |
| Before |
1 u - 2 |
1 u + 8 |
| Change |
+ 2 |
- 8 |
| After |
1 u |
1 u |
Total value of $20 and $5 notes remains unchanged after the exchange of notes of similar value.
Total value of 8 pieces of $5-notes
= 8 x 5
= $40
Number of $20-notes that 8 pieces of $5-notes were exchanged for
= 40 ÷ 20
= 2
| In the end |
$20 |
$5 |
Total |
| Number |
1 u |
1 u |
2 u |
| Value |
20 |
5 |
|
| Total Value |
20 u |
5 u |
25 u |
Total value of $20 and $5 notes
= 20 u + 5 u
= 25 u
25 u = 900
1 u = 900 ÷ 25 = 36
Number of $5 notes at first
= 1 u + 8
= 36 + 8
= 44
Answer(s): 44
