A jar contained $5 and $50 notes with a total value of $1375. 10 pieces of $50 were exchanged for $5 notes of similar value. In the end, the number of $5 notes was the same as the $50 notes. How many $50 notes were there at first?
| |
$5 |
$50 |
| Before |
1 u - 100 |
1 u + 10 |
| Change |
+ 100 |
- 10 |
| After |
1 u |
1 u |
Total value of $5 and $50 notes remains unchanged after the exchange of notes of similar value.
Total value of 10 pieces of $50-notes
= 10 x 50
= $500
Number of $5-notes that 10 pieces of $50-notes were exchanged for
= 500 ÷ 5
= 100
| In the end |
$5 |
$50 |
Total |
| Number |
1 u |
1 u |
2 u |
| Value |
5 |
50 |
|
| Total Value |
5 u |
50 u |
55 u |
Total value of $5 and $50 notes
= 5 u + 50 u
= 55 u
55 u = 1375
1 u = 1375 ÷ 55 = 25
Number of $50 notes at first
= 1 u + 10
= 25 + 10
= 35
Answer(s): 35
