A jar contained $2 and $10 notes with a total value of $228. 6 pieces of $10 were exchanged for $2 notes of similar value. In the end, the number of $2 notes was the same as the $10 notes. How many $10 notes were there at first?
|
$2 |
$10 |
Before |
1 u - 30 |
1 u + 6 |
Change |
+ 30 |
- 6 |
After |
1 u |
1 u |
Total value of $2 and $10 notes remains unchanged after the exchange of notes of similar value.
Total value of 6 pieces of $10-notes
= 6 x 10
= $60
Number of $2-notes that 6 pieces of $10-notes were exchanged for
= 60 ÷ 2
= 30
In the end |
$2 |
$10 |
Total |
Number |
1 u |
1 u |
2 u |
Value |
2 |
10 |
|
Total Value |
2 u |
10 u |
12 u |
Total value of $2 and $10 notes
= 2 u + 10 u
= 12 u
12 u = 228
1 u = 228 ÷ 12 = 19
Number of $10 notes at first
= 1 u + 6
= 19 + 6
= 25
Answer(s): 25