A jar contained $50 and $5 notes with a total value of $1375. 10 pieces of $5 were exchanged for $50 notes of similar value. In the end, the number of $50 notes was the same as the $5 notes. How many $5 notes were there at first?
|
$50 |
$5 |
Before |
1 u - 1 |
1 u + 10 |
Change |
+ 1 |
- 10 |
After |
1 u |
1 u |
Total value of $50 and $5 notes remains unchanged after the exchange of notes of similar value.
Total value of 10 pieces of $5-notes
= 10 x 5
= $50
Number of $50-notes that 10 pieces of $5-notes were exchanged for
= 50 ÷ 50
= 1
In the end |
$50 |
$5 |
Total |
Number |
1 u |
1 u |
2 u |
Value |
50 |
5 |
|
Total Value |
50 u |
5 u |
55 u |
Total value of $50 and $5 notes
= 50 u + 5 u
= 55 u
55 u = 1375
1 u = 1375 ÷ 55 = 25
Number of $5 notes at first
= 1 u + 10
= 25 + 10
= 35
Answer(s): 35