A jar contained $10 and $50 notes with a total value of $2340. 11 pieces of $50 were exchanged for $10 notes of similar value. In the end, the number of $10 notes was the same as the $50 notes. How many $50 notes were there at first?
|
$10 |
$50 |
Before |
1 u - 55 |
1 u + 11 |
Change |
+ 55 |
- 11 |
After |
1 u |
1 u |
Total value of $10 and $50 notes remains unchanged after the exchange of notes of similar value.
Total value of 11 pieces of $50-notes
= 11 x 50
= $550
Number of $10-notes that 11 pieces of $50-notes were exchanged for
= 550 ÷ 10
= 55
In the end |
$10 |
$50 |
Total |
Number |
1 u |
1 u |
2 u |
Value |
10 |
50 |
|
Total Value |
10 u |
50 u |
60 u |
Total value of $10 and $50 notes
= 10 u + 50 u
= 60 u
60 u = 2340
1 u = 2340 ÷ 60 = 39
Number of $50 notes at first
= 1 u + 11
= 39 + 11
= 50
Answer(s): 50