A jar contained $50 and $20 notes with a total value of $1260. 5 pieces of $20 were exchanged for $50 notes of similar value. In the end, the number of $50 notes was the same as the $20 notes. How many $20 notes were there at first?
|
$50 |
$20 |
Before |
1 u - 2 |
1 u + 5 |
Change |
+ 2 |
- 5 |
After |
1 u |
1 u |
Total value of $50 and $20 notes remains unchanged after the exchange of notes of similar value.
Total value of 5 pieces of $20-notes
= 5 x 20
= $100
Number of $50-notes that 5 pieces of $20-notes were exchanged for
= 100 ÷ 50
= 2
In the end |
$50 |
$20 |
Total |
Number |
1 u |
1 u |
2 u |
Value |
50 |
20 |
|
Total Value |
50 u |
20 u |
70 u |
Total value of $50 and $20 notes
= 50 u + 20 u
= 70 u
70 u = 1260
1 u = 1260 ÷ 70 = 18
Number of $20 notes at first
= 1 u + 5
= 18 + 5
= 23
Answer(s): 23