A jar contained $2 and $5 notes with a total value of $238. 12 pieces of $5 were exchanged for $2 notes of similar value. In the end, the number of $2 notes was the same as the $5 notes. How many $5 notes were there at first?
|
$2 |
$5 |
Before |
1 u - 30 |
1 u + 12 |
Change |
+ 30 |
- 12 |
After |
1 u |
1 u |
Total value of $2 and $5 notes remains unchanged after the exchange of notes of similar value.
Total value of 12 pieces of $5-notes
= 12 x 5
= $60
Number of $2-notes that 12 pieces of $5-notes were exchanged for
= 60 ÷ 2
= 30
In the end |
$2 |
$5 |
Total |
Number |
1 u |
1 u |
2 u |
Value |
2 |
5 |
|
Total Value |
2 u |
5 u |
7 u |
Total value of $2 and $5 notes
= 2 u + 5 u
= 7 u
7 u = 238
1 u = 238 ÷ 7 = 34
Number of $5 notes at first
= 1 u + 12
= 34 + 12
= 46
Answer(s): 46