A jar contained $2 and $5 notes with a total value of $245. 8 pieces of $5 were exchanged for $2 notes of similar value. In the end, the number of $2 notes was the same as the $5 notes. How many $2 notes were there at first?
|
$2 |
$5 |
Before |
1 u - 20 |
1 u + 8 |
Change |
+ 20 |
- 8 |
After |
1 u |
1 u |
Total value of $2 and $5 notes remains unchanged after the exchange of notes of similar value.
Total value of 8 pieces of $5-notes
= 8 x 5
= $40
Number of $2-notes that 8 pieces of $5-notes were exchanged for
= 40 ÷ 2
= 20
In the end |
$2 |
$5 |
Total |
Number |
1 u |
1 u |
2 u |
Value |
2 |
5 |
|
Total Value |
2 u |
5 u |
7 u |
Total value of $2 and $5 notes
= 2 u + 5 u
= 7 u
7 u = 245
1 u = 245 ÷ 7 = 35
Number of $2 notes at first
= 1 u - 20
= 35 - 20
= 15
Answer(s): 15