A jar contained $10 and $50 notes with a total value of $1320. 6 pieces of $50 were exchanged for $10 notes of similar value. In the end, the number of $10 notes was the same as the $50 notes. How many $50 notes were there at first?
|
$10 |
$50 |
Before |
1 u - 30 |
1 u + 6 |
Change |
+ 30 |
- 6 |
After |
1 u |
1 u |
Total value of $10 and $50 notes remains unchanged after the exchange of notes of similar value.
Total value of 6 pieces of $50-notes
= 6 x 50
= $300
Number of $10-notes that 6 pieces of $50-notes were exchanged for
= 300 ÷ 10
= 30
In the end |
$10 |
$50 |
Total |
Number |
1 u |
1 u |
2 u |
Value |
10 |
50 |
|
Total Value |
10 u |
50 u |
60 u |
Total value of $10 and $50 notes
= 10 u + 50 u
= 60 u
60 u = 1320
1 u = 1320 ÷ 60 = 22
Number of $50 notes at first
= 1 u + 6
= 22 + 6
= 28
Answer(s): 28