A jar contained $50 and $10 notes with a total value of $2040. 5 pieces of $10 were exchanged for $50 notes of similar value. In the end, the number of $50 notes was the same as the $10 notes. How many $10 notes were there at first?
|
$50 |
$10 |
Before |
1 u - 1 |
1 u + 5 |
Change |
+ 1 |
- 5 |
After |
1 u |
1 u |
Total value of $50 and $10 notes remains unchanged after the exchange of notes of similar value.
Total value of 5 pieces of $10-notes
= 5 x 10
= $50
Number of $50-notes that 5 pieces of $10-notes were exchanged for
= 50 ÷ 50
= 1
In the end |
$50 |
$10 |
Total |
Number |
1 u |
1 u |
2 u |
Value |
50 |
10 |
|
Total Value |
50 u |
10 u |
60 u |
Total value of $50 and $10 notes
= 50 u + 10 u
= 60 u
60 u = 2040
1 u = 2040 ÷ 60 = 34
Number of $10 notes at first
= 1 u + 5
= 34 + 5
= 39
Answer(s): 39