A jar contained $2 and $50 notes with a total value of $1508. 8 pieces of $50 were exchanged for $2 notes of similar value. In the end, the number of $2 notes was the same as the $50 notes. How many $50 notes were there at first?
| |
$2 |
$50 |
| Before |
1 u - 200 |
1 u + 8 |
| Change |
+ 200 |
- 8 |
| After |
1 u |
1 u |
Total value of $2 and $50 notes remains unchanged after the exchange of notes of similar value.
Total value of 8 pieces of $50-notes
= 8 x 50
= $400
Number of $2-notes that 8 pieces of $50-notes were exchanged for
= 400 ÷ 2
= 200
| In the end |
$2 |
$50 |
Total |
| Number |
1 u |
1 u |
2 u |
| Value |
2 |
50 |
|
| Total Value |
2 u |
50 u |
52 u |
Total value of $2 and $50 notes
= 2 u + 50 u
= 52 u
52 u = 1508
1 u = 1508 ÷ 52 = 29
Number of $50 notes at first
= 1 u + 8
= 29 + 8
= 37
Answer(s): 37
