Bryan bought some papayas and pears in the ratio of 2 : 5 respectively. The cost of one papaya was $0.50 more than the cost of one pear. He spent a total of $30 buying the papayas and pears. The total cost of the pears was $10 more than the total cost of the papayas. How much did one papaya cost?
| |
Papayas |
Pears |
Total |
| Number of sets |
2 sets |
5 sets |
|
| Compare each |
$0.50 more |
|
|
| Total value |
|
$10 more |
$30 |
Total cost of papayas
= (30 - 10) ÷ 2
= 20 ÷ 2
= $10
Total cost of pears
= 10 + 10
= $20
2 sets of papayas = $10
1 set of papayas = 10 ÷ 2 = $5
5 sets of pears = $20
1 set of pears = 20 ÷ 5 = $4
Difference in cost of 1 set of papayas and 1 set of pears
= 5 - 4
= $1
Number of fruits in 1 set
= 1 ÷ 0.50
= 2
Cost of one papaya
= 5 ÷ 2
= $2.50
Answer(s): $2.50
