Reggie bought some apples and oranges in the ratio of 3 : 7 respectively. The cost of one apple was $0.50 more than the cost of one orange. He spent a total of $129 buying the apples and oranges. The total cost of the oranges was $39 more than the total cost of the apples. How much did one apple cost?
| |
Apples |
Oranges |
Total |
| Number of sets |
3 sets |
7 sets |
|
| Compare each |
$0.50 more |
|
|
| Total value |
|
$39 more |
$129 |
Total cost of apples
= (129 - 39) ÷ 2
= 90 ÷ 2
= $45
Total cost of oranges
= 45 + 39
= $84
3 sets of apples = $45
1 set of apples = 45 ÷ 3 = $15
7 sets of oranges = $84
1 set of oranges = 84 ÷ 7 = $12
Difference in cost of 1 set of apples and 1 set of oranges
= 15 - 12
= $3
Number of fruits in 1 set
= 3 ÷ 0.50
= 6
Cost of one apple
= 15 ÷ 6
= $2.50
Answer(s): $2.50
