Asher bought some mangosteens and papayas in the ratio of 3 : 7 respectively. The cost of one mangosteen was $1.40 more than the cost of one papaya. He spent a total of $171 buying the mangosteens and papayas. The total cost of the papayas was $39 more than the total cost of the mangosteens. How much did one papaya cost?
| |
Mangosteens |
Papayas |
Total |
| Number |
3 sets |
7 sets |
|
| Value |
$1.40 more |
|
|
| Total value |
|
$39 more |
$171 |
Total cost of mangosteens
= (171 - 39) ÷ 2
= 132 ÷ 2
= $66
Total cost of papayas
= 66 + 39
= $105
3 sets of mangosteens = $66
1 set of mangosteens = 66 ÷ 3 = $22
7 sets of papayas = $105
1 set of papayas = 105 ÷ 7 = $15
Difference in cost of 1 set of mangosteens and 1 set of papayas
= 22 - 15
= $7
Number of fruits in 1 set
= 7 ÷ 1.40
= 5
Cost of one papaya
= 15 ÷ 5
= $3
Answer(s): $3
